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If s−x/4= s−y/3=s-z/2 and area of inci...

If s−x/4= s−y/3=s-z/2 and area of incircle of the triangle XYZ is 8(pi)/3 thenThe radius of the circumcircle of `!XYZ`

A

`35/(sqrt6)`

B

`(35/(2sqrt6)`

C

`35/(4sqrt6)`

D

`35/(6sqrt6)`

Text Solution

Verified by Experts

`s=9,s-x=(4s)/9,s-y=(3s)/9,s-z=(2s)/9` and `Delta=6sqrt6`
`thereforex=5,y=6` and z=7
Hence, `R=(xyz)/(4Delta)`
`rArrR=(5xx6xx7)/(4xx6sqrt6)=35/(4sqrt6)`
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