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Statement-1: ln !ABC,r(1)+r(2)+r(3)-r=4R...

Statement-1: ln `!ABC,r_(1)+r_(2)+r_(3)-r=4R`
Statement-2: In `!ABC,r_(1)r_(2)+r_(2)r_(3)+r_(3)r_(1)=!^(2)`

A

Statement-1 is True, Statement-2 is true, Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement- 2 is True.

Text Solution

Verified by Experts

Statement-1 is true.
now, `r_(1)r_(2)+r_(2)r_(3)+r_(3)r_(1)`
`=(!^(2))/((s-a)(s-b))+(!^(2))/((s-b)(s-c))+(!^(2))/((s-c)(s-a))`
`=(!^(2))/((s-a)(s-b)(s-c)){3s-(a+b+c)}=s^(2)`
So, statement-2 is not true.
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