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If AD, BE and CF are the medians of a AB...

If AD, BE and CF are the medians of a ABC ,then `(AD^(2)+BE^(2)+CF^(2)):(BC^(2)+CA^(2)+AB^(2))` is equal to

A

`4:3`

B

`3:2`

C

`3:4`

D

`2:3`

Text Solution

Verified by Experts

The correct Answer is:
C
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