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In a triagnle ABC, angle B=pi/3 " and ...

In a triagnle ABC, `angle B=pi/3 " and " angle C = pi/4` let D divide BC internally in the ratio 1:3 .Then `(sin (angle BAD))/((Sin (angle CAD))` is equal to

A

`(1)/(sqrt6)`

B

`1/3`

C

`1/sqrt3`

D

`sqrt((2/3))`

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