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If in a triangleABC=(a)/(cos A)=(b)/(cos...

If in a `triangleABC=(a)/(cos A)=(b)/(cos B)`, then

A

2 sin A sin B sin C=1

B

`sin^(2) A+sin^(2)B=sin^(2)C`

C

2 sin A cos B=sin C

D

none of these

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The correct Answer is:
C
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