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If "tan" (pi "cos" theta) = "cot"(pi "s...

If `"tan" (pi "cos" theta) = "cot"(pi "sin" theta),` then the value(s) of `"cos" (theta-(pi)/(4))`, is (are)

A

`(1)/(2)`

B

`(1)/(sqrt(2))`

C

`+-(1)/(2sqrt(2))`

D

none of these

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The correct Answer is:
To solve the equation \( \tan(\pi \cos \theta) = \cot(\pi \sin \theta) \), we can follow these steps: ### Step 1: Rewrite the equation using cotangent We know that \( \cot(x) = \frac{1}{\tan(x)} \). Therefore, we can rewrite the equation as: \[ \tan(\pi \cos \theta) = \frac{1}{\tan(\pi \sin \theta)} \] This implies: \[ \tan(\pi \cos \theta) \tan(\pi \sin \theta) = 1 \] ### Step 2: Use the identity for tangent Using the identity \( \tan(A) \tan(B) = 1 \) leads us to: \[ \pi \cos \theta + \pi \sin \theta = \frac{\pi}{2} + n\pi \quad (n \in \mathbb{Z}) \] This simplifies to: \[ \cos \theta + \sin \theta = \frac{1}{2} + n \] ### Step 3: Rearranging the equation Rearranging gives us: \[ \cos \theta + \sin \theta = 2n + \frac{1}{2} \] ### Step 4: Use the cosine of angle subtraction formula We want to find \( \cos\left(\theta - \frac{\pi}{4}\right) \). Using the cosine subtraction formula: \[ \cos\left(\theta - \frac{\pi}{4}\right) = \cos \theta \cos \frac{\pi}{4} + \sin \theta \sin \frac{\pi}{4} \] Since \( \cos \frac{\pi}{4} = \sin \frac{\pi}{4} = \frac{1}{\sqrt{2}} \), we have: \[ \cos\left(\theta - \frac{\pi}{4}\right) = \frac{1}{\sqrt{2}} (\cos \theta + \sin \theta) \] ### Step 5: Substitute the value of \( \cos \theta + \sin \theta \) Substituting the value from Step 3: \[ \cos\left(\theta - \frac{\pi}{4}\right) = \frac{1}{\sqrt{2}} \left(2n + \frac{1}{2}\right) \] ### Step 6: Simplify the expression This simplifies to: \[ \cos\left(\theta - \frac{\pi}{4}\right) = \frac{2n + \frac{1}{2}}{\sqrt{2}} = \frac{4n + 1}{2\sqrt{2}} \] ### Step 7: Find specific values of \( n \) To find specific values, we can substitute \( n = 0 \) and \( n = -1 \): - For \( n = 0 \): \[ \cos\left(\theta - \frac{\pi}{4}\right) = \frac{1}{2\sqrt{2}} \] - For \( n = -1 \): \[ \cos\left(\theta - \frac{\pi}{4}\right) = \frac{-1}{2\sqrt{2}} \] ### Final Answer Thus, the values of \( \cos\left(\theta - \frac{\pi}{4}\right) \) are: \[ \frac{1}{2\sqrt{2}} \quad \text{and} \quad \frac{-1}{2\sqrt{2}} \] ---
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