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If x = X "cos" theta-Y "sin" theta, y = ...

If `x = X "cos" theta-Y "sin" theta, y = X "sin" theta + Y "cos" theta " and " x^(2) + 4xy + y^(2) =AX^(2) + BY^(2), 0 le theta le (pi)/(2), n in Z`, then

A

`theta = (pi)/(6), A = 3, B = 1`

B

`theta = (pi)/(4), A = 3, B =1`

C

`A =3, B=-1, theta = (pi)/(4)`

D

`A = -3, B = 1, theta = (pi)/(4)`

Text Solution

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The correct Answer is:
C
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