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The upper (3/4)^(th) portion of a vertic...

The upper `(3/4)^(th)` portion of a vertical pole subtends an angle `"tan"^(-1)3/5` at a point in the horizontal plane through its foot at a distance 40 m from the foot . A possible height of the vertical pole is

A

80 m

B

20 m

C

40 m

D

60 m

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The correct Answer is:
To solve the problem step-by-step, we will use trigonometric relationships and the information provided in the question. ### Step 1: Understand the Problem We have a vertical pole of height \( h \). The upper \( \frac{3}{4} \) portion of the pole subtends an angle of \( \tan^{-1} \left( \frac{3}{5} \right) \) at a point 40 m away from the foot of the pole. We need to find the height \( h \) of the pole. ### Step 2: Define the Variables Let: - \( AB \) be the height of the pole \( h \). - \( CD \) be the upper \( \frac{3}{4} \) portion of the pole, which is \( \frac{3}{4}h \). - \( AD \) be the lower \( \frac{1}{4} \) portion of the pole, which is \( \frac{1}{4}h \). - The distance from the foot of the pole to the point on the ground is \( 40 \) m. ### Step 3: Set Up the Trigonometric Relationship The angle \( D \) subtended by the upper \( \frac{3}{4} \) portion at point \( C \) can be expressed in terms of tangent: \[ \tan D = \frac{CD}{AC} = \frac{\frac{3}{4}h}{40} \] We know from the problem that \( D = \tan^{-1} \left( \frac{3}{5} \right) \), so: \[ \tan D = \frac{3}{5} \] ### Step 4: Equate the Two Expressions for Tangent Now we can set the two expressions for \( \tan D \) equal to each other: \[ \frac{\frac{3}{4}h}{40} = \frac{3}{5} \] ### Step 5: Solve for \( h \) Cross-multiplying gives: \[ 3 \cdot 40 = \frac{3}{4}h \cdot 5 \] \[ 120 = \frac{15}{4}h \] Multiplying both sides by \( \frac{4}{15} \): \[ h = \frac{120 \cdot 4}{15} = \frac{480}{15} = 32 \text{ m} \] ### Step 6: Verify the Calculation To ensure the calculation is correct, we can double-check: 1. \( \frac{3}{4}h = \frac{3}{4} \cdot 32 = 24 \) m. 2. \( \tan D = \frac{24}{40} = \frac{3}{5} \), which matches the given angle. ### Conclusion The possible height of the vertical pole is: \[ \boxed{32 \text{ m}} \]
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