The resistance of `0.5M` solution of an electrolyte in a cell was found to be `50 Omega`. If the electrodes in the cell are `2.2 cm` apart and have an area of `4.4 cm^(2)` then the molar conductivity (in `S m^(2) mol^(-1))` of the solution is

The resistance of 0.5 N solution of an electrolyte in a conductivity cell was found to be 45 ohms. If the electrodes in the cell are 2.2 cm apart and have an area of 3.8 cm^2 then the equivalent conductance (in Scm^2 eq^(-1) ) of a solution is

The resistance of 0.5 N solution of an electroolyte in a conductivity cell was found to be 45 ohms. If the electrodes in the cell are 2.2 cm apart and have an area of 3.8cm^(2) then the equivalent conductance (in Scm^(2)eq^(-1) ) of a solution is

The resistance of 0.25 M solution of an electrolyte was found to be 75 Omega . Calculate molar conductivity of the solution, if the electrodes in the cell are 1.8 cm apart and have an area of cross section 3.6 cm^2 .

The resistance of N//5 solution of an electrolyte in a cell was found to be 45 ohm. Calculate the equivalent conductance of the solution if the electrodes in a cell are 2.2 cm apart and have an area of 3.8 equiv. cm.

The resistance of a 0.5M solution of an electrolyte was found to be 30Omega . Calculate the molar conductivity of the solution if the electrods in the cell are 1.5 cm a part and having an area of cross section is 2.0 cm^(2) .

The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of 3*2cm^(2) .