`K_(a)` of `HA` is `10^(-4)`. The equilibrium constant for its reaction with a strong base is

A certain weak acid has a dissocation constant of 1.0 xx 10^(-4) . The equilibrium constant for its reaction with a strong base is

A certain weak acid has a dissocation constant of 1.0 xx 10^(-4) . The equilibrium constant for its reaction with a strong base is

A certain weak acid has K_(a), = 10^(-5) . If the equilibrium constant for is its reaction with a strong base is repesented as yxx 10^(y) then find the value of y.

A certain weak acid has a dissociation constant 1.0xx10^(-4) . The equilibrium constant for its reaction with a strong base is :

A certain weak acid has a dissociation constant 1.0xx10^(-4) . The equilibrium constant for its reaction with a strong base is :

A certain weak acid HA has a dissociation constant of 1 times 10^(-4) at 298 K. The equilibrium constant for its reaction with the strong base NaOH is

A certain weak acid has a dissociation constant of 1.0xx10^-4 M . The equilibrium constant for its reaction with a strong base is:

A certain weak acid has K_(a)=10^(-5). If the equilibrium constant for it reaction with a strong base is represented as 1xx10^(y) then find the value of y.