A `50` g lead bullet (specific heat `0.02`) is initially at `30^(@)C`. It is fired vertically upward with a speed of `840 ms^(-1)`. On returning to the starting level it strikes a cake of ice at `0^(@)C`. How much ice is melted ? Assume that all energy is spent in melting only. Latent heat of ice `=336 j g^(-1)`.

A 50gram lead bullet, specific heat 0.02 is initially at 30^(@) C. It is fired vertically upwards with a speed of 840 m// s . On returning to the starting level, it strikes a cake of ice at 0^(@)C . How much ice is melted ? Assume that all energy is spent in melting ice only. Take latent heat of ice = 80 cal. // gram.

A 50 gm lead bullet (sp. Heat 0.020 cal//g) is initially at 30^(@)C . It is fired vertically upward with a speed 84 m//s On returning to the starting level, it strikes a slab of ice at 0^(@)C . (Axx100) mg of ice is melted. Find the value of 'A' .

At 30^(@) C, a lead bullet of 50 g, is fired verticaly upwards with a speed of 840 m/s. The specific heat of leasd is 0.02 cal/ g^(@) C. On returning to the starting level, it strikes to a cake of ice at 0^(@) C. Calcualte the amount of ice melted (Assume all the energy is spent in melting only)

How much heat energy is required to melt 5 kg of ice ? Specific latent heat of ice = 336 J g^(-1)

How much heat energy is required to melt 5 kg of ice? (Specific latent heat of ice = 336 Jg^(-1) )

When 1 g of ice melts at 0^@C

The entropy change in melting 1g of ice at 0^@C . (Latent heat of ice is 80 cal g^(-1) )