[" 20."(5)/(x+1)-(2)/(y-1)=(1)/(2)],[(10)/(x+1)+(2)/(y-1)=(5)/(2),x!=-1" and "y!=1]

Solve the following system of equations: (5)/(x+1)-(2)/(y-1)=(1)/(2),quad (10)/(x+1)+(2)/(y-1)=(5)/(2) where x!=-1 and y!=1

( 5 ) /( x+ 1 ) - (2)/(y - 1 ) = (1)/(2) , (10)/(x + 1) + ( 2 ) /( y - 1) = ( 5)/(2), x ne - 1 and y ne 1

Solve the following system of equations: 5/(x+1)-2/(y-1)=1/2,\ \ \ (10)/(x+1)+2/(y-1)=5/2 , where x!=-1 and y!=1

If (5)/(x-1)+(1)/(y-2)=2,(6)/(x-1)+(-3)/(y-2)=1 then x=……….

{:((5)/(x - 1) + (1)/(y - 2) = 2),((6)/(x - 1) - (3)/(y - 2) = 1):}

(5) / (x-1) + (1) / (y-2) = 2 (6) / (x-1) - (3) / (y-2) = 1

Solve : (1)/(2x)+(1)/(4y)-(1)/(3z)=(1)/(4),(1)/(x)=(1)/(3y),(1)/(x)-(1)/(5y)+(4)/(z)=2 (2)/(15)

solve for x and y . (5)/(x-1)+(1)/(y-2) =2 and ( 6) / ( x-1) -(3)/ (y-2) =1

The solution of (dy)/(dx)=(1)/(2x-y^(2)) is given by , (A) y=Ce^(-2x)+(1)/(4)x^(2)+(1)/(2)x+(1)/(4)," 4"(1)/(2)," (B) "x=Ce^(-y)+(1)/(4)y^(2)+(1)/(4)y+(1)/(2)," (C) "x=Ce^(y)+(1)/(4)y^(2)+y+(1)/(2)," (D) "x=Ce^(2y)+(1)/(2)y^(2)+(1)/(2)y+(1)/(4)