`(dy)/(dx)` ज्ञात कीजिए|
`x=a(theta-sin theta), y=a(1+cos theta)`

x=a(theta-sin theta),y=a(1+cos theta) find dy/dx

x = a (theta - sin theta), y = a (1 + cos theta) find dy/dx

If x=-a(theta-sin theta),y=a(1-cos theta), then (dy)/(dx) is

x = a (theta + sin theta), y = a (1 - cos theta) find dy/dx

If x=a(theta+sin theta),quad y=a(1+cos theta), find (dy)/(dx)

Find (dy)/(dx), when x=a(theta+sin theta) and y=a(1-cos theta)

If x=a ( theta -sin theta ) ,y=a(1-cos theta ) ,then (dy)/(dx) =

If x and y are connected parametrically by the equations given in Exercises 1 to 10, without eliminating the parameter, Find (dy)/(dx) . x= a (cos theta+ theta sin theta), y= a (sin theta-theta cos theta) .