Show that the function f: R-> R : f(x)=s...

Show that the function `f: R-> R : f(x)=sinx` is neither one-one nor onto

Verified by Experts

`Sinx` is many-one
into functions
`f(x_1)=f(x_2)`
`sinx_1=sinx_2`
`x_1!=x_2`
`y=sinx`
`x=sin^(-1)y`
`y=sin^(-1)x`
...

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