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From 200mg of CO(2),10^(21) molecuels ar...

From 200mg of `CO_(2),10^(21)` molecuels are removed. How many moles of `CO_(2)` are left?

Text Solution

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Gram-molecular mass of `CO_(2)=44g`
Mass of `10^(21)` molecuels of `CO_(2)=(44)/(6.02xx10^(23))xx10^(21)=0.073g`
Mass of `CO_(2)` left `=(0.2-0.073)=0.127g`
Number of moles of `CO_(2)` left `=(0.127)/(44)=2.88xx10^(-3)`
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