How many electrons are present in 1.6 g of methane?

Explanation

Gram molecular mass of methane, ltbr. `(CH_(4))=12+4=16g`
Number of moles in 1.6g of methane.
`=(1.6)/(16)=0.1`
Number of molecules of methane in 0.1 mole
`=0.1xx6.02xx10^(23)`
`=6.02xx10^(22)`
One molecule of methane has =6+4=10electrons
So, `6.02xx10^(22)` molecules methane have
`10xx6.02xx10^(22)` electrons
`=6.02xx10^(23)` electrons