Show that the following results illustrate the law of reciprocal proportions:
(i) 0.92g Mg produces 1.54g mangesium oxide.
(ii) 0.41 g Mg illustrates 380mL of hydrogen at NTP from on acid.
(iii) 1.25g of water results from the union of 1.11 g of oxygen with hydrogen.
(Density of hydrogen at NTP=0.00009g `mL^(-1)`)

Explanation

(i) Mass of oxygen =(1.54-0.92)=0.62g
0.92g Mg combines with 0.62g of oxygen
1g Mg combines with oxygen `=(0.62)/(0.92)=0.6739g`
(ii) Mass of 380mL of hydrogen at NTP `=380xx0.00009g`
`=0.0342g`
0.41g Mg liberates hydrogen =0.0342g
1g Mg liberates hydrogen `=(0.0342)/(0.41)=0.0834g`
The ratio of hydrogen and oxygen which combine with 1g Mg is
`0.0834:0.6739`, i.e., 1:8
(iii) Mass of hydrogen `=(1.25-1.11)=0.14g`
The ratio of hydrogen and oxygen in water =0.14:1.11 or 1:8
Sine, the ratio of hydrogen and oxygen is same, the law of reciprocal is illustrated.