Air contains 20% oxygen by volume. Calculating the theoretical volume of air which will be required for burning 200 `m^(3)` of acetylene gas completely. All volumes are measured under the same conditions of temperature and pressure.

Explanation

`{:(2C_(2)H_(2),+,SO_(2),rarr,4CO_(2),+,2H_(2)O(g)),("2vol",,"5vol",,"4vol",,"2vol"),("1vol",,"2.5vol",,"2vol",,"2vol"):}`
Thus , 500 `m^(3)` oxygen is required for complete combustion of 200 `m^(3)` of acetylene, 20 `m^(3)` of oxygen is present in 100 `m^(3)` of air.
`500 m^(3)` of oxygen will be present in `=(100)/(20)xx50m^(3)` of air
`=2500 m^(3)` of air