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Calcualte the number of oxygen atoms in ...

Calcualte the number of oxygen atoms in 88g `CO_(2)`. What would be the mass of CO having the same number of oxygen atoms?

Text Solution

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88g `CO_(2)=2` moles of `CO_(2)` One molecule consists of 2 oxygen atoms.
No. of oxygen atoms `=2xx2xx6.02xx10^(23)=24.08xx10^(23)`
CO molecuel has one oxygen atom.
Mass of CO containing 24.08`xx 10^(23)` oxygen atoms
`=(28)/(6.02xx10^(23))xx24.08xx10^(23)=112g`
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Knowledge Check

  • 8 g of O_(2) has the same number of oxygen atoms as

    A
    `11g CO_(2)`
    B
    14 g of CO
    C
    32 g of `SO_(2)`
    D
    8g `O_(3)`

  • The number of oxygen atoms in 4.4 of CO_(2) is

    A
    `1.2xx10^(23)`
    B
    `6xx10^(22)`
    C
    `6xx10^(23)`
    D
    `12xx10^(23)`

  • What will be the weight of CO having the same number of oxygen atoms as present in 22g of CO_2 ?

    A
    28 g
    B
    22g
    C
    44 g
    D
    72g

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