If the equivalent mass of a metal (M) is x and the formula of its oxide is `M_(m)O_(n)`, then show that the atomic mass of M is `(2xn)/(m)`

Explanation

m atoms of M combine with n atoms of oxygen
1 atom of M combines with `(n)/(m)` atoms of oxygen
Hence, valencey`=(2n)/(m)`
Atomic mass=Equivalent mass `xx` Valency.
`x xx(2n)/(m)=(2nx)/(m)`