In `m_(1)g` of a metal A displaces `m_(2)G` of another metal B from its salt solution and if their equivalent masses are `E_(1)` and `E_(2)` respectively, then the equivalent mass of A can be expressed as:

Options

A. `E_(1)=(m_(2)xxE_(2))/(m_(1))`
B. `E_(1)=(m_(1))/(m_(2))xxE_(2)`
C. `E_(1)=(m_(1)xxm_(2))/(E_(2))`
D. `E_(1)=sqrt((m_(1))/(m_(2))xxE_(2))`

Answer

B