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An element X has the following isotopic ...

An element X has the following isotopic composition,
`.^(200)X:90%`
`.^(199)X:8%`
`.^(2002)X:2%`
the weighted average atomic mass of the naturally-occurring element 'X' is closed to:

A

201amu

B

202amu

C

199amu

D

200amu

Text Solution

Verified by Experts

The correct Answer is:
D
Average atomic mass of
`X=[(99)/(100)xx200]+[(8)/(100)xx199]+[(2)/(100)xx202]`
`=199.96` amu =200amu.
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