Volume occupied by one molecule of water (density =`1g//cm^(3)`) is:

Options

A. `3xx10^(-23)cm^(3)`
B. `5.5xx10^(-23)cm^(3)`
C. `9xx10^(-23)cm^(3)`
D. `6.023xx10^(-23)cm^(3)`

Answer

A

Explanation

Mass of one molecule`=(18)/(6.023xx10^(23))g`
`=2.98xx10^(-23)g`
Volume of one molecule `=(M)/("Density")=(2.98xx10^(-23))/(1)cm^(3(`
`=3xx10^(-23)cm^(3)`