A plant virus consists of uniform cylindrical particles of 150 `overset(@)A` in diamter and `5000overset(@)A` long. The specific volume of virus is 0.75 `cm^(3)`/g. if the virus is considered to be a single particle, its molecular mass is:

Options

A. `7.09xx10^(7)g "mol"^(-1)`
B. `7.90xx10^(7)g "mol"^(-12)`
C. `9.07xx10^(7)g "mol"^(-1)`
D. `9.70xx10^(7)g "mol"^(-1)`

Answer

A

Explanation

Volume of single virus `=pir^(2)h`
`=3.14xx(75xx10^(-8))^(2)xx(5000xx10^(-8))`
`=8.836xx10^(-17)cm^(3)`
Mass of single virus `=("Volume")/("Specific volume")=(8.836xx10^(-17)cm^(3))/(0.75cm^(3)//g)`
`=1.178xx10^(-16)g`
Molar mass of virus `=1.178xx10^(-16)xx6.023xx10^(23)`
`=7.09xx10^(7)g "mol"^(-1)`