5.85 g NaCl is dissovled in 1L water. The number of ions of `Na^(+)` and `Cl^(-)` in 1 mL of this solution will be:

Options

A. `6.02xx10^(19)`
B. `1.2xx10^(22)`
C. `1.2xx10^(20)`
D. `6.02xx10^(20)`

Answer

C

Explanation

Number of moles of NaCl
`=("Mass")/("Molar mass")=(5.95)/(58.5)=0.1`
Number of ions `(Na^(+)+Cl^(-))` in 1L
`=2xx01xx6.023xx10^(23)`
`=12.046xx10^(22)`
Number of ions in 1mL `=(12.046xx10^(22))/(1000)=1.2xx10^(20)`