10 mL of mixture containing carbon monoxide and nitrogen required 7mL, oxygen to form `CO_(2)` and NO, on combustion The volume of `N_(2)` in the mixture will be:

Options

A. 7/2mL
B. 17/2mL
C. 4mL
D. 7mL

Answer

C

Explanation

`CO(g)+(1)/(2)O_(2)(g)rarrCO_(2)(g)`
`N_(2)(g)+O_(2)(g)rarr2NO(g)`
`x+y=10`
`(x)/(2)+y=7`
Solving eqs, i and ii,
`x=6` and y=4