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5g H(2) is allowed to react with 14 g N(...

5g `H_(2)` is allowed to react with 14 g `N_(2)` for the following reaction.
`N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)`
What mass of `H_(2)` will be left unreached at the end of reaction?

Text Solution

Verified by Experts

The correct Answer is:
2
`N_(2)` os ,o,otomg reactamt. Thus `14 g N_(2)` will give 17g `NH_(3)` and xg `H_(2)` remains unreacted.
Mass before reaction =Mass after reaction
`(5+14)=(17+x)`
x=2g
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