Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound.
Molecular formula=(Empirical formula)`xxn`
`n=("Molecular mass")/("Empirical formula mass")`
A compound may have same empirical and molecular formulae Both these formulae are calculated by using percentage composition of constituent elements.
The pair of species having different percentage composition of carbon are:

Options

A. `CH_(3)COOH` and `C_(6)H_(12)O_(6)`
B. `CH_(3)COOH` and `C_(2)H_(5)OH`
C. `HCOOCH_(3)` and `HCOOH`
D. `C_(2)H_(5)OH` and `CH_(3)OCH_(3)`

Answer

B, C