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In the given figure AB is a chord of a c...

In the given figure AB is a chord of a circle, with centre O, such that `AB=16 cm` and radius of circle is 10 cm. Tangent at A and B intersect each order at P. Find the length of PA.

Text Solution

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AB=16cm AL=AB/2=8cm
In `/_OAL`
`AL^2+OL^2=OA^2` So we get, OL=6cm Hence,` tan(theta)=(OA)/(PA)=(OL)/(AL)` `(PA)=(OA)*(AL)/(OL)` Therefore, PA=80/6=40/3.
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