`int(cosx-sinx+1-x)/(e^x+sinx+x)dx=ln(f(x))+g(x)+c` where C is the constant of integration and `f(x)` is positive, then `f(x)+g(x)` has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. Then f(x)+g(x) has the value equal to

int(cosx-sinx+1-x)/(e^(x)+sinx+x)dx=log_(e)(f(x))+g(x)+C where C is the constant of integration and f(x) is positive. The f(x)+g(x) has the value equal to a) e^(x)+sinx+2x b) e^(x)+sinx c) e^(x)-sinx d) e^(x)+sinx+x

If int(x(sin x-cos x)-sin x)/(e^(x)+(sin x)x)dx=-ln(f(x))+g(x)+C where C is the constant of integration and f(x) is positive then f(x)+g(x) has the value equal to

If int (cos x-sin x + 1-x)/(e^(x)+sin x+x)dx=ln{f(x)}+g(x)+C , where C is the constant of integrating and f(x) is positive, then (f(x)+g(x))/(e^(x)+sin x) is equal to .......... .

if int xe^(2x) dx = e^(2x).f(x)+c , where c is the constant of integration, then f(x) is

If inte^(sinx)[(xcos^3x-sinx)/(cos^2x)]dx=e^(sinx)*f(x)+c , where c is constant of integration, then f(x)=

If intxe^(2x)dx is equal to e^(2x)f(x)+c , where c is constant of integration, then f(x) is