log((36)/(25))^(3)+3log(2)/(9)-log2=2log(16)/(125)quad (" purod ")

Prove that log(36/25)^(3)+3log(2/9)-log2=2log(16/125)

Simplify : (iii) 3log((36)/(25))+log((6)/(27))^(3)-2log((16)/(125))

7log((10)/(9))-2log((25)/(24))+3log((81)/(80))

7log((10)/(9))-2log((25)/(24))+3log((81)/(80))=log2

log5-(log25)/(2^(2))+(log125)/(3^(2))-(log625)/(4^(2))+ ……

log5-(log25)/(2^(2))+(log125)/(3^(2))-(log625)/(4^(2))+ ……

The value of (3log_(2)((81)/(80))+5log_(2)((25)/(24))+7log_(2)((16)/(15))) is

log root(3)(6(2)/(9))=(1)/(3)(log7-2log3)+log2

Express in terms of log 2 and log 3 : (i) log 36 (ii) log 144 (iii) log 4.5 (iv) "log"(26)/(51) - "log" (91)/(119) (v) "log"(75)/(16) - "2 log" (5)/(9) + "log" (32)/(243)

((1)/(2))log9+2log3-log6+log2-2