At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point `( 4, 3)`. Find the equation of the curve given that it passes through `(2, 1)`.

At any point P(x,y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact P to the point (-4,-3) Find the equation of the curve given that it passes through the point (-2, 1)

At any point (x,y) of a curve,the slope of the tangent is twice the slope of the line segment joining the point of contact to the point Find the equation of the curve given that it passes through quad (-2,1)

A curve passes through the point (-2, 1) and at any point (x, y) of the curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (-4, -3). Find the equation of the curve.

The slope of a curve at any point is the reciprocal of twice the ordinate at that point and it passes through the point (4,3). The equation of the curve is:

The slope of a curve at any point is the reciprocal of twice the ordinate at that point and it passes through the point(4,3). The equation of the curve is:

The slope of the tangent to the curve at any point is equal to y + 2x. Find the equation of the curve passing through the origin .

The slope of the tangent to the curve at any point is equal to y + 2x. Find the equation of the curve passing through the origin .

The slope of the tangent at any point on a curve is lambda times the slope of the line joining the point of contact to the origin. Formulate the differential equation and hence find the equation of the curve.

A curve passes through the point (3,-4) and the slope of the tangent to the curve at any point (x,y) is (-(x)/(y)) . Find the equation of the curve.