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(7)/(x)+35=(1)/(10)...

(7)/(x)+35=(1)/(10)

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7x+(3)/(x)=35(3)/(5)

Solve by factorization: 7x+(3)/(x)=35(3)/(5)

Solve: (3x)/(7)-(4)/(35)=(2x)/(5)

What percent of (2)/(7) is (1)/(35)?25% (b) 20%15% (d) 10%

What percent of (2)/(7) is (1)/(35) ?

Factorize: x^(2)+(12)/(35)x+(1)/(35)

Lt_(x to oo)((1)/(3.5)+(1)/(5.7)+.....+(1)/((2n+1)(2n+3)))=

(x-3)/(5)+(x-4)/(7)=6-(2x-1)/(35)

int_(256)^( pi)sqrt(2)(1+cos x)^((7)/(2))dx=(A)(32)/(35)(B)(64)/(35)(C)(256)/(35)(D)(512)/(35)