Find the minimum length of radius vector of the curve `(a^2)/(x^2)+(b^2)/(y^2)=1`

The minimum radius vector of the curve a^2/x^2+b^2/y^2=1 is

Show that the minimum distance of a point on the curve (a^(2))/(x^(2)) + (b^(2))/(y^(2)) = 1 from the origin is a + b.

Find the angle of intersection of curve (x^2)/(a^2)+(y^2)/(b^2)=1 and x^2+y^2=a b

Find the angle of intersection of curve (x^2)/(a^2)+(y^2)/(b^2)=1 and x^2+y^2=a b

A point on the curve (x ^(2))/(A ^(2)) - (y^(2))/(B ^(2)) =1 is

A point on the curve (x ^(2))/(A ^(2)) - (y^(2))/(B ^(2)) =1 is

Find the equation of the normal to the curve (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 at (x_(0),y_(0))