[sin^(2)5^(@)+sin^(2)10^(@)+sin^(2)15^(@)+.....],[+sin^(2)85^(@)+sin^(2)90^(@)" Chris will be equal "]

sin^(2)5^(@)+sin^(2)10^(@)+sin^(2)15^(@)+ .....+sin^(2)85^(@)+sin^(2)90^(@) is equal to

sin^(2) 5^(@)+sin^(2) 10^(@) +sin^(2)15^(@)+...+sin^(2) 180^(@)=

sin^(2) 75^(@) - sin^(2)15^(@)=

sin^(2)5^(@) + sin^(2)25^(@) + sin^(2)45^(@) + sin^(2) 65^(@) + sin^(2) 85^(@) is equal to:

Show that sin^(2)5^(@)+sin^(2)10^(@)+sin^(2)15^(@)+.....+sin^(2)90^(@)=9(1)/(2)

The value of sin^(2) 1^(@) + sin^(2) 2^(@) + sin^(2) 3^(@)+ . . . . + sin^(2) 89^(@) + sin ^(2) 90^(@) is

sin^(2)21^(@) + sin^(2) 69^(@) is equal to