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Given that 1/(2!17!)+1/(3!16!)+1/(4!15!)...

Given that `1/(2!17!)+1/(3!16!)+1/(4!15!)+...+1/(8!11!)+1/(9!10!)=N/(1!18!)`, find floor `(N/100)`. Here, floor(x) is the greatest integer less than or equal to x.

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