" The straight line "(1+2i)z+(2i-1)z=10i" on the complex plane,has intercept on the imagily "

The straight line (1+2 iota)z+(2 iota-1)bar(z)=10 iota on the complex plane,then the intercept on imaginary axis

Let i=sqrt(-1) Define a sequence of complex number by z_(1)=0,z_(n+1)=(z_(n))^(2)+i for n>=1. In the complex plane,how far from the origin is z_(111)?

Let i=sqrt(-1) Define a sequence of complex number by z_1=0, z_(n+1) = (z_n)^2 + i for n>=1 . In the complex plane, how far from the origin is z_111 ?

Let i=sqrt(-1) Define a sequence of complex number by z_1=0, z_(n+1) = (z_n)^2 + i for n>=1 . In the complex plane, how far from the origin is z_111 ?

Let i=sqrt(-1) Define a sequence of complex number by z_1=0, z_(n+1) = (z_n)^2 + i for n>=1 . In the complex plane, how far from the origin is z_111 ?

Consider four complex numbers z_(1)=2+2i, , z_(2)=2-2i,z_(3)=-2-2iandz_(4)=-2+2i),where i=sqrt(-1), Statement - 1 z_(1),z_(2),z_(3)andz_(4) constitute the vertices of a square on the complex plane because Statement - 2 The non-zero complex numbers z,barz, -z,-barz always constitute the vertices of a square.

Consider four complex numbers z_(1)=2+2i, , z_(2)=2-2i,z_(3)=-2-2iandz_(4)=-2+2i),where i=sqrt(-1), Statement - 1 z_(1),z_(2),z_(3)andz_(4) constitute the vertices of a square on the complex plane because Statement - 2 The non-zero complex numbers z,barz, -z,-barz always constitute the vertices of a square.

Consider four complex numbers z_(1)=2+2i, , z_(2)=2-2i,z_(3)=-2-2iandz_(4)=-2+2i),where i=sqrt(-1), Statement - 1 z_(1),z_(2),z_(3)andz_(4) constitute the vertices of a square on the complex plane because Statement - 2 The non-zero complex numbers z,barz, -z,-barz always constitute the vertices of a square.