sin^(-1)x+sin^(-1)y=sin^(-1)(x sqrt(1-y^(2))+y)*1-x^(2)

sin^(-1)x+sin^(-1)y=sin^(-1)(x sqrt(1-y^(2))+y sqrt(1-x^(2))) then find the area represented by the locus of point (x,y) if |x|<=1,|y|<=1

Prove that : sin^(-1)x+sin^(-1)y=sin^(-1)(xsqrt(1-y^2)+ysqrt(1-x^2))

sin^(-1)x+sin^(-1)y=cos^(-1)(sqrt(1-x^(2))sqrt(1-y^(2))-xy) if x in[0,1],y in[0,1]

sin^(-1)x+sin^(-1)y=cos^(-1)""{sqrt((1-x^(2))(1-y^(2)))-xy}

Prove the following: sin^-1x-sin^-1y = sin^-1[x(sqrt(1-y^2))-y(sqrt(1-x^2))]

sin^(- 1)x+sin^(- 1)y=cos^(- 1) (sqrt(1-x^2) sqrt(1-y^2)-xy) if x in [0,1], y in [0,1]

If sin^(-1)x+sin^(-1)y+sin^(-1)z=pi prove that x sqrt(1-x^(2))+y sqrt(1-y^(2))+z sqrt(1-z^(2))=2xyz

tan ^(-1)x-tan ^(-1)y=sin ^(-1) ""(x-y)/(sqrt((1+x^(2))(1+y^(2)))

sin^-1 x+ sin^-1 y = sin^-1[x 1-y^2 + y 1- x^2]