If f(x)={(ax^2+b ,0lex<1),(4,x=1),(x+3,...

If `f(x)={(ax^2+b ,0lex<1),(4,x=1),(x+3,1ltxge2))` then the value of`(a ,b)` for which `f(x)` cannot be continuous at `x=1,` is (a)`(2,2)` (b) `(3,1)`(c)`(4,0)` (d)`(5,2)`

Similar Questions

Explore conceptually related problems

The funtion f(x) is defined as follows: f(x) = {:{(x^2+ax+b,0lex<2),(3x+2,2lexle4),(2ax+5b,4 < xle8):} If f(s) is continuous on [0,8], find the values of 'a' and 'b'.

If f(x)={ax^(2)+b,x 1;b!=0, then f(x) is continuous and differentiable at x=1 if

Examine the differentiability of the function f(x) = {:{(x[x], if 0 lex<2),((x-1)x,if2lex<3):} at x =2

A single formula that gives f(x) for all x gt 0 , where f(x)={(2+x",",0lex lt 2),(3x-2",",x ge 2):} is

Let f(x)={:{[x^(2) if xlex_(0)], [ax +b if xgtx_(0)]:} if 'f' is differentiable at x_(0) then

If f(x)=ax^(2)+bx+c , show that , underset(hrarr0)"lim"(f(x+h)-f(x))/(h)=2ax+b

Let f(x) =ax^(2) -b|x| , where a and b are constants. Then at x = 0, f (x) is

Is the following function invertible in the respective domain ? If so, find the inverse : f(x) = sqrt(1-x^2), 0lex le1 .

If `f(x)={(ax^2+b ,0lex<1),(4,x=1),(x+3,1ltxge2))` then the value of`(a ,b)` for which `f(x)` cannot be continuous at `x=1,` is (a)`(2,2)` (b) `(3,1)`(c)`(4,0)` (d)`(5,2)`

Similar Questions

Recommended Questions