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Given 3[[x, y],[ z, w]]=[[x,6],[-1, 2w]]...

Given `3[[x, y],[ z, w]]=[[x,6],[-1, 2w]]+[[4,x+y],[ z+w,3]]`, find the values of x, y, z and w.

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solution
`3[[x, y],[ z, w]]=[[x,6],[-1, 2w]]+[[4,x+y],[ z+w,3]]`
`[[3x, 3y],[ 3z, 3w]]=[[x+4,6+x+y],[z+w-1, 2w+3]]`
`3x=x+4` ⇒`2x=4 ⇒x=2`
`3y=6+x+y ⇒2y=6+x=6+2=8 ...
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