The solution of the differential equation `dy/dx=y tanx-2 sinx` is

Explanation

`dy/dx = ytanx-2sinx`

`=>dy/dx - ytanx = -2sinx`



Comparing the given equation with first order differential equation,

`dy/dx+Py = Q(x)`, we get,
`P = -tanx and Q(x) = -2sinx`

So, Integrating factor `(I.F) = e^(int -tandx)`

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