Light of frequency .25 `v_0` is incident on a metal surface of threshold frequency 2`v_0`. If its frequency is halved and intensity is made three times then find the new value of photoelectric current.

Frequency of radiation incident on metal surface is called threshold frequency.

A photon of frequency v is incident on a metal surface whose threshold frequency is v_(0) . The kinetic energy of the emitted photoelectrons will be

Light of frequency v is incident on a certain photoelectric substance with threshold frequency v . The work function for the substance is

Photons of frequency, v, fall on metal surface for which the threshold frequency is v_(0) . Then

Light of frequency v is incident on a substance of threshold frequency v(v lt v) . The energy of the emitted photo-electron will be

Light of frequency 4 v_(0) is incident on the metal of the threshold frequency v_(0) . The maximum kinetic energy of the emitted photoelectrons is

Light of frequency 4nu_0 is incident on the metal of the threshold frequency nu_0 . The maximum kinetic energy of the emitted photoelectric is

Threshold frequency for metal surface is 4xx10^(14) Hz.When radiation of 5xx10^(14) Hz is incident on this surface ,photo-electric current obtained is 1.8 mA.If frequency of incident radiation is made half and intensity is made three times,value of photo-electric current will be.....

Light of frequency 1.5 times the threshold frequency is incident on photo-sensitive material. If the frequency is halved and intensity is doubled, the photocurrent becomes