The equations of bisectors of two lines `L_1 & L_2` are `2x-16y-5=0` and `64x+ 8y+35=0`. lf the line `L_1` passes through `(-11, 4)`, the equation of acute angle bisector of `L_1` & `L_2` is:

The bisector of two lines L and L are given by 3x^2 - 8xy - 3y^2 + 10x + 20y - 25 = 0 . If the line L_1 passes through origin, find the equation of line L_2 .

The bisector of two lines L and L are given by 3x^(2)-8xy-3y^(2)+10x+20y-25=0. If the line L_(1) passes through origin,find the equation of line L_(2).

The equation of the bisector of the acute angle between the lines 2x-y+4=0 and x-2y=1 is

theta_1 and theta_2 are the inclination of lines L_1 and L_2 with the x-axis. If L_1 and L_2 pass through P(x_1,y_1) , then the equation of one of the angle bisector of these lines is

theta_1 and theta_2 are the inclination of lines L_1 and L_2 with the x-axis. If L_1 and L_2 pass through P(x_1,y_1) , then the equation of one of the angle bisector of these lines is

theta_(1) and theta_(2) are the inclination of lines L_(1) and L_(2) with the x axis.If L_(1) and L_(2) pass through P(x,y) ,then the equation of one of the angle bisector of these lines is

Given equation of line L_1 is y = 4 Find the equation of L_2 .

Consider two lines L_1:2x+y=4 and L_2:(2x-y=2) Find the equation of the line passing through the intersection of L1 and L2 which makes an angle 45° with the positive direction of x-axis .

Consider two lines L_1:2x+y=4 and L_2:(2x-y=2) Find the equation of the line passing through the intersection of L_1 and L_2 which makes an angle 45° with the positive direction of x-axis . Find the x and y intercepts of the third line obtained.