Calculate difference in binding energy of atomic hydrogen and atomic deuterium.

Explanation

B.E. of `._(1)^(1)H=13.6 eV`
Considering motion of nucleus
`B.E. of ._(1)^(1)H=(M)/(m+M)xx13.6 eV`
`B.E. Of ._(1)^(2)H=(2M)/(m+2M)xx13.6 eV`
where M : mass of `._(1)^(1)H` nucleus.
`B.E. "of " ._(1)^(2)H-B.E. " of " ._(1)^(2)H-B.E. "of " ._(1)^(2)H=13.6[(2M)/(m+2M)-(M)/(m+M)]`
" " `= Mxx13.6((m)/((m+2M)(m+M)))`
" " `=13.6[(mM)/((m+2M)(m+M))]`
M=1837 m
`=(13.6xx1837)/(3675xx1838)=3.69xx10^(-3) eV`