In a Rutherford scattering experiment when a projectile of change `Z_(1)` and mass `M_(1)` approaches s target nucleus of change `Z_(2)` and mass `M_(2)`, te distance of closed approach is `r_(0)`. The energy of the projectile is

Options

A. directly proportional to `M_(1) xx M_(2)`
B. directly proportional to `Z_(1)Z_(2)`
C. inversely proportional to `Z_(1)`
D. directly proportional to mass `M_(1)`

Answer

B

Explanation

`(1)/(2)M_(1)v^(2)=(1)/(4 pi epsilon_(0)).(Z_(1)Z_(2)e^(2))/(r_(0))`
`K=(1)/(4 pi epsilon_(0)).(Z_(1)Z_(2)e^(2))/(r_(0)), K prop Z_(1)Z_(2)`