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The enrgy of an atom (or ion) in the gro...

The enrgy of an atom (or ion) in the ground state is `- 54.4 eV ` .If may be

A

hydrogen

B

deuterium

C

`He^(+)`

D

`Li^(++)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(n)=-13.6(Z^(2))/(n^(2))eV`
`-54.4=-13.6(Z^(2))/(1^(2)) implies Z^(2)=4`
Z=2
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