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The radius of the shortest orbit in a on...

The radius of the shortest orbit in a one electron system is 18 pm it may be

A

hydrogen

B

deuterium

C

`He^(+)`

D

`Li^(++)`

Text Solution

Verified by Experts

The correct Answer is:
D
`r_(n)=0.53(n^(2))/(Z)` Å
`18xx10^(-12)=(0.53(1)^(2))/(Z)xx10^(-10)`
Z=3
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