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Let A(0) be the area enclined by the orb...

Let `A_(0)` be the area enclined by the orbit in a hydrogen atom .The graph of in `(A_(0) //A_(1))` against `ln(n)`

A

(i), (ii)

B

(ii), (iii)

C

(i), (iii)

D

(ii), (iv)

Text Solution

Verified by Experts

The correct Answer is:
A
`(A_(n))/(A_(1))=(pi r_(n)^(2))/(pi r_(1)^(2))=((0.53 n^(2))/(0.53))^(2)=n^(4)`
Taking log on both sides
In `((A_(n))/(A_(1))) =" In "n^(4)=4 " In " n implies y=4x`
In `((A_(n))/(A_(1))) v//s` In n graph will be straight line of slope 4.
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