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if the electron in hydrogen orbit jumps...

if the electron in hydrogen orbit jumps form third orbit to second orbit, the wavelength of the emitted radiation is given by

A

`(36)/(5 R)`

B

`(5R)/(36)`

C

`(6)/(5 R)`

D

`(5 R)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(lambda)=Z^(2)R((1)/(2^(2))-(1)/(3^(2)))=R ((1)/(4)-(1)/(9))=(5R)/(36)`
` lambda=(36)/(5R)`
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