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Four lowest energy levels of H-atom are ...

Four lowest energy levels of `H`-atom are shown in the figure. The number of possoble emission lines would be

A

3

B

4

C

5

D

6

Text Solution

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The correct Answer is:
D

Number of lines `=((n_(2)-n_(1))(n_(2)-n_(1)+1))/(2)=(3xx4)/(2)=6`
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